0=-16x^2-40x+328

Solution for 0=-16x^2-40x+328 equation:

0=-16x^2-40x+328

We move all terms to the left:

0-(-16x^2-40x+328)=0

We add all the numbers together, and all the variables

-(-16x^2-40x+328)=0

We get rid of parentheses

16x^2+40x-328=0

a = 16; b = 40; c = -328;
Δ = b2-4ac
Δ = 402-4·16·(-328)
Δ = 22592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22592}=\sqrt{64*353}=\sqrt{64}*\sqrt{353}=8\sqrt{353}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-8\sqrt{353}}{2*16}=\frac{-40-8\sqrt{353}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+8\sqrt{353}}{2*16}=\frac{-40+8\sqrt{353}}{32}
$